2x^2-6x-35=0

Solution for 2x^2-6x-35=0 equation:

2x^2-6x-35=0

a = 2; b = -6; c = -35;
Δ = b2-4ac
Δ = -62-4·2·(-35)
Δ = 316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{316}=\sqrt{4*79}=\sqrt{4}*\sqrt{79}=2\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{79}}{2*2}=\frac{6-2\sqrt{79}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{79}}{2*2}=\frac{6+2\sqrt{79}}{4}
$